c# - SkipWhileIterator method implementation understanding -

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I'm reading that CLR can take it, for example, what is happening when implementing the SkipWhile method. : 

  IList & lt; String & gt; Numbers = New list & lt; String & gt; () {"one two three four five"}; Var results = numbers While skip (number = & gt; number = thumb == 3); result. Toolist () (Number => console WrightLine (number)) for;

CLR will do these steps:

The C # compiler uses an anonymous method ( to be a method & lt; main & gt; B__1 number = & gt; number. length == 3 ) in compile time. As a definition of & lt; CLR left time Main & gt; Using the b__1 method will instal an example of multicast delegate . Using the CLR original list, give an example of the SkipWhileIterator iterator, and & lt; Main & gt; B__1 Due to suspended execution, SkipWhileIterator CLR does not call toList call or ForEach method To repeat through the uses, CLR runs the toList method to SkipWhileIterator on SkipWhile , and SkipWhileIterator Inside , under the CLR original list, execute uniform on each of the items and if the information is incorrect, then S KipWhileIterator returns the code as the result of the SkipWhile method;

So far, everything is fine.

However, I have seen the implementation of SkipWhileIterator . 

  Fixed IEnumerable & lt; TSource & gt; SkipWhileIterator & lt; TSource & gt; (IEnumerable & lt; TSource & gt; source, functic & lt; TSource, bool & gt; predicate) {bool yielding = false; FORECA (tsos element in source) {if (! Yield and !; ADYT) yield = true; If yield (returns) yield returns element; }}

But, is not it wrong? In my opinion the second statement should be like that: 

  if (yield) {yield = false; Yield returns element};

The value of the prevailing should be set to false on the other side, , otherwise if the value is not found within the statement then the value is true .

Thank you.

Once leave gets a value that does not match the ingenuity The account stops seeing it and just returns the rest of the sequence yield starts false, so that the elements will not return, and it will be set to the right on the non-match first. After this, it does not want to make the statement again in the first if because it already knows that after that the elements are going to return.


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