python - Regex url pattern for django -

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I need to define the URL pattern for the URL below 

  http: // Myurl: 8080 / authentication / agent / newpassword /? Reset Powered = Text Value and AggressCode = Text Value

I tried the following, but I have 404 

  url (r '^

What I'm doing wrong here.

/ P>

The message receiving the error 

  "Received / Authentication / Agent / New password / Reset paced = text value and agentcode = text value HTTP / 1.1 "302 0

You match query string with Django url pattern

Use the following pattern: 

  url (r '^ authentication / agent / newpassword / $', password validation),  < / Pre> 
 and in the view, use the  request to get the GET parameter:  
  defect password verification (request): reset password = request.GET.get ( 'Resetpassword', '') agentCode = request.GET.get ('agentCode', '')

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