perl - Determine if directory is the root directory -

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I am searching for the name of the directory, if the directory is found, give me the code chdir In other words, otherwise give an error message. For example: 

  Use warnings; Strict use; Use cdwd getcwd; Die "base directory not found!" If (! Gaotier ()); All goto {my $ baseDir = '.test'; My $ curdir = getcwd (); While (1) {return 1 if (-d $ baseDir); If (Chdir ("..")) {chdir ($ curdir); Return 0; The problem is that  chdir  is not unsuccessful after going out of the root, so the above program enters an infinite loop if  .test  is not found. 
 
 Of course, when I'm on Linux, I could just test for  / , but I want to do it independently in a system. / P> 
 
 As @GNUK replied, the original directory portable with its  rootdir in the module The representation is  the method. 
 
 In this way I will write my  goto_dir  subroutine to note that capital letters are traditionally reserved for global identifiers such as  Package :: Names . I think it is best to pass that directory which you are searching for as a parameter in sub-routine Make it more general I have also written that substantine is a  chdir  to  .test < / Code> in the directory if it is found, which you say you want, but not your own solution tries to do this. 
 
 Finally, since portability is important, I have a  in place of '..' instead of  file :: spice- & gt; Updir  has used  to reference the origin of the current directory.  
  #! Use / usr / bin / env perl strict; Use warnings; Cwd use 'cwd'; Use the file: Spec; Goto_dir ('test') or dead 'base directory was not found!'; All goto_rate {my ($ base_dir) = @_; My $ original_dir = cwd; While () {if (-d $ base_dir) {chdir $ base_dir; Return 1; } Elsf (CWD ek file :: spice-> RootDIR) {chdir $ original_dir; Return 0; } And {chdir file :: device-> updir; }}}

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