java - How do I get all nodes in a scene in JavaFX? -

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In C #, I found a way that was pretty sweet, from which you control all the tribes and all their descendants.

I am looking for a similar method for Java FX.

I have seen that the parent class is the one with which I want to work because this is the category from which all the node classes that raise the children are taken.

This is what I have done so far (and I actually did not find anything on Google with "JavaFX finding all the nodes from one view"): 

  Public Fixed Arrestist & lt; Node & gt; GetAllNodes (Generate Route) {ArrayList & lt; Node & gt; Descendents = new ArrayList & lt; & Gt; (); Root.getChildrenUnmodifiable (). Stream (). For every (n -> (Descendents.contains (N)) Descendents.add (N); if (N.getClass () == Parent.class) Descendents.addAll (GetAllNodes (guardian))) ;}); }

So how would I tell that N is a parent (or extended by parents)? Am I doing this right? It is not working ... This root (parent) is in grabbing all the nodes from the node, but not with the children in the nodes. I think there is something like that probably got the answer but I'm just asking questions ... wrong. How can I go about doing this? 

  public static array list & lt; Node & gt; GetAllNodes (Generate Route) {ArrayList & lt; Node & gt; Nodes = new arrelisted & lt; Node & gt; (); AddAllDescendents (Routes, Nodes); Return nodes; } Private static zero addAllDescendents (parent, ArrayList & nt; node & node) nodes {for (node ​​node: parent.getChildrenUnmodifiable ()) {nodes.add (node); If (parent node example) addAllDescendents ((parent) nodes, nodes); }}

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