haskell - zipWith-ing List of Integers with List of Functions -

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How do I make [integer] with a [integer - & Gt; Integer - & gt; Integer] to get the [integer - & gt; Integer] ?

Example:

I tried: 

  prelude & gt; With desired result of [1,2,3] (3 (*))

with zip:

[(* 1), ( * 2), (* 3)]

But I got an error: 

  & lt; Interactive>: 25: 9: Could not match the expected type `(A0 - & gt; a0 - & gt; a0) - & gt; B - 0 - & gt; In the first argument of 'zip with' with the actual type '[T]', in the expression '[1, 2, 3]', in the expression: zip [1, 2, 3] (repeat 3 (*)) In the equation for an 'this': it = zip [1, 2, 3] (repeat 3 (*))

edit me right - thanks .

It seems that I can do it with applicants: 

  prelude control. Epicclic & gt; F f = [(*)]

But, can I do this with the zipWith ?

You were close to an operator for the application, $ , which exactly Useful in such cases. 

  & gt; : T ZIP ($) [(*), (*), (*)] [1..3] ZIP ($) [(*), (*), (*)] [1..3]: (Number B, NUM B) = & gt; [B -> B]

And if you want [1..3] first, this zip hash (flip ($)) .

Additionally, your appetite variant is wrong, if this causes: 

  & gt; F f = [(*), (*), (*)]

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