Spring security get User object -

I have implemented user authentication through the Spring security framework and everything works well I can log in and log For example, for example, I can log in for example:

  string user name = (auth.getPrincipal) ()). GetUsername ();  

Now I have to get an object from the database from the database (I need the User ID and other user properties).

How I have tried it yet:

  user user = (user) SecurityContextHolder.getContext (). GetAuthentication (). GetPrincipal ();  

Then I got an exception:

  The request process failed; Nested exception java.lang Class upstation: org.springframework.security.core.userdetails.User can not be entered on net.viralpatel.contact.model.User  

Here is a question - how do I user As the object can be obtained, how should I modify my classes UserDetailsServiceImpl and UserAssembler, any ideas? @Component @Transactional Public Class UserDetailsServiceImpl applies UserDetailsService {@Autowired Personal UserDAO userDAO; @ Owned Personal UserAsseller UserAssamler; Private Static Final Logar Logar = LogfinerGetLoggers (User DeveloperCPCPM Class); @ Transactional (Read Only = True) Public UserDuffload UsernameByUUN Name (String Username) Username Notfound Exceptions, Data EntactionExation {User User = Username FDBEEMM (Username); If (zero == user) new user name notfound exception ("user not found"); Return userasubable.bilduserformuesuser (user); }}

and another:

  @ service ("enveloper") public class UserAssembler {@Autowired Private UserDAO userDAO; @transcensive (read only = true) public user builderframe user (net virilpatel contact.model.user user) {string roll = "ROLE_USER"; // User AntiTADO Gatorol FormUSAATTE (UserEnty); Collections & lt; GrantedAuthority & gt; Officials = new Arrestists & lt; Valid Authority & gt; (); Rights.add (new licensing authority Impl (role); New users (user.getLogin (), user.getPassword (), true, true, truthful, return the authorities); }}  

Basically, you UserDetails > Access the user .

You have two options:

• Add your user as a field (you can call it org.springframework .security.core.userdetails.User ):

    public class UserPrincipal ORG.fr springframework.Ssecurity extends .core.userdetails.User {Personal End User Users ; ...}  

  and get a user from that area:

    object prize = SecurityContextHolder.getContext (). GetAuthentication () .getPrincipal (); User user = (Principal principal (userpin)) .getUser ();  

• Create a class that implements your user and implements UserDetails : < / P>

    public class UserPrincipal uses user UserDetails {... public UserPrincipal (user user) {// copy fields user from}}  

  This approach You can see the principal user directly:

    user user = (user) SecurityContextHolder.getContext (). GetAuthentication (). GetPrincipal ();