haskell - Error on comparing IO Int inside of a lambda -

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I have a small section of code here that I want to use in a statement. Code 

  getRandomInt :: (Int, Int) - & gt; IO Int getRandomInt (A, B) = GG & lt; - newStdGen return. Fst $ randomR (a, b) g

then forward down ... 

  if ((getRandomInt (0,1)) gt; & gt; ; = (\ X -> x == 1))

Under my understanding, it should be compiled at randomInt == 1 and one If the statement is usable within the statement; I get this error: 

  word.hs: 30: 21: The actual type 'IOB' with the expected type 'Bull' could not be matched with expression: ((getRandomInt (0, 1)) & gt; & gt; = (\ x - & gt; x == 1)) In a STM of a 'do' block: if ((getRandomInt (0, 1)) gt; & gt; ; = (\ X -> X == 1)) Get the getendord: getWord $ len-1 and get the derANDindex: getWord $ len-1 in expression: do {if (getRandomInt (0, 1 ))> Gt;> = (\ x -> X == 1) getRandomVowel: (getWord $ len - 1) and get Rendendum alert A: Sorry for any clear misconceptions, I just yesterday

-text "itemprop =" text ">

type (& gt; & gt; =) is Monad M => I'm a - & gt; (A -> Mb) - & gt; MB In this case M = Io .

Then you have two problems:

First of all, \ x -> X == 1 a bool will not return, it will not be a IO bool , so it (>>> =) .

You can decide that it should be \ x -> Returns (x == 1) , but this is not a very clear solution and then you feel that the result is Bool instead of IO Bool / P>

This is the error that is telling you - if requires a Bool argument but got it IO something .

The perfect solution getRandomInt is a separate & lt; - To lift in line: 

  x

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