java - Quick one: clarity or short code? -

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OK, like I did a quick promise, so we go here:

The piece is found in in in.split (""); to mark the string, so I get all the characters separately and then remove those people I do not want, and currently it looks like this:

list & lt; String & gt; Op = new array list & lt; String & gt; (Arrays.asList (in.split (""))); Op.removeAll (removable); Operators = op.toArray (new string [op.size ()]);

Where op is my temporary variable to delete. Is there any way to put it in one line? And if there (pls tell me how, i was thinking for some time and i thought that there is not because removeAll () boolean gives) - should it be done or should i Should It Be Easy To Read?

If you want to remove the alphabet, regex will be a better option than an array of string characters, and You do not need to use a list to process it. 

  Remove the string = "[a-zA-Z0-9]"; String operators = in.replaceAll (removable, "");

This gives you a string of non-removable characters.

If there is a removable archive, you can turn it back into a string.

String Reggae = "[" + (Removable. Stream.) (Collectors. Joining ())) + "]"; String operators = in.replaceAll (regex, "");

You can inline it to create a liner to regex .

If you want to remove words, you need Java 8 to stream it in a serial (unless you write a method to do that, Line) 

  list & lt; String & gt; Operator = stream.f (insupeit (""). Filter (S ->! Removable seamants) .collect (collectors list);

However, to make it readable, you can still end up using three new lines. ;)


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