javascript - How to remove element with empty attr on page load -

-

I am using an entry which depends on how to add jQuery's entry to an overlay, depending on which The image is clicked which works well. But if no image is inserted then I want to remove the containerImage img . This is the closest I got to click and remove empty tags, but I want to do it on page load.

$ (document) .ready (function () {var $ container = $ ("# container image img"); $ container.click (function () {if ($ container.ttR ("Src") === "") {$ (this) .remove ();} else {console.log ("not empty");}}};});

Here the HTML in the IMG tag is, I'm calling the images to go into the empty source

So the above example has only 2 images, I want to remove that box after leaving it with a 3 empty box and after filling the images.

Here is the code to fill images, as well as title and description 

  $ (document) .ready (function () {$ ('. BoxImage') Click (function () (var project = $ (this) .attr ('project'), description = $ (this) .attr ('description'), images = $ (this) .attr ('images'); $ ("Text"); $ ("projects description"). Text (description); var image array = images (such as ','); datloged (image array);}); function deferred (array) {// $ ('.gallery thumbnail'); $ thumbnail.ttr ('scom', ''); (var i = 0; i & lt; 5; i ++) {$ ('. Gallery thumbnail: eq (' + ' I '' '). Attr (' src ', array [i]);}}});

$ thumbnails.filter ("[src = '']") .remove ();

First of all, keep in mind that:

is an invalid closing tag for & lt; IMG & gt; (IMG is a self-closing tag)
Image , Description , and project are invalid HTML attributes. (Use the data - * attributes) 

  & lt; Img src = "" class = "Boxing Gallery Thumbnail" & gt; & Lt; Img src = "" class = "Boxing Gallery Thumbnail" & gt; & Lt; Img src = "" class = "Boxing Gallery Thumbnail" & gt; & Lt; Img src = "image / image 1.jpg" class = "box image w2" data-project = "project title" data-description = "description" data-images = "pictures / 4.jpg, pictures / 5.jpg" & Gt; Click here (function () {var data = $ (this Data (); $ ("Projects"). Text (Data Pauses); $ ("Projects Description"). Text (Data Description); Datoded (Data.immes.plit (','));} $ Var (thumbnail); $ thumbnail = $ ('gallery thumbnail'); $ thumbnail.ttr ('scom', ''); for (var i = 0; i    
    
 Now this is what I do not understand ... if you remove your images You do not have any  src  attribute  dom ready , your script fills the reason for any image ... well, it has been removed .

Comments

Post a Comment

Popular posts from this blog

html - Trouble with image gallery on codepen -

-
I get my first project html & amp; CSS, but there is some problem. I am practicing using Codepean and my gallery was running well but I am trying to add the last line of images and it is all messing up and I do not know why For some reason, when I try to add that chess board it all gets worse. I am still very new so I hope to learn a lot. Thank you. [1]: http://codepen.io/zenturtle/pen/ezDGC Margins are causing issues when you use margins in the position of an element, then you push the elements around it too. Use a solution: Status: Relative and then use Positioning Properties: Above , Below , left , right example: #chess {status: relative; Left: 555px; } Another solution is to use status: absolute . Location Location: Relative on & lt; Div id = "perimeter" & gt; Status: Full on every Example: #chess {status: full; Bottom: 122px; Correct: 230px; } Similarly you are in the position of chess image...
Read more

java - org.apache.http.ProtocolException: Target host is not specified -

-
I have written a simple httprequest / response code and I am getting this error below: I used to type in my classpath httpclient, httpcore, common -Codecs and general logging. I am very new to Java and I do not know what's going on here. Please help me. code: import org.apache.http.client.HttpClient; Import org.apache.http.client.methods.HttpGet; Import org.apache.http.HttpResponse; Import org.apache.http.impl.client.HttpClientBuilder; Import org.apache.http.Header; Import org.apache.http.HttpHeaders; Public class UnshorteningUrl {public static zero main (string [] args throws exception {HttpGet request = zero; HTTP Client Client = HTTP ClientBuilder.credit (). Build (); Try {Request = New HTTP Gate ("trib.me/1lBFzSi"); HttpResponse httpResponse = client.execute (request); Header [] header = httpResponse.getHeaders (HttpHeaders.LOCATION); // Preconditions.checkState (headers.length == 1); String new url = header [0] .getValue (); System.out.println ("new url...
Read more

How to access user directory in lazarus? -

-
After I am trying to open file changelog.txt and it does not matter if I open it Need to have the user open it though it is always located in the ~ / directory. Enter the file here. Here is my code: Process TForm1.FormCreate (From: TObject); Var myFile: textfile; Line: String; Start AssignFile (myFile, '~ / changelog.txt'); Reset (myFile); While EOF (MyFile) does not readLn (myFile, Line); Label3.Caption: = (Label3.Capttion + Line + # 13 # 10); End; CloseFile (myFile); End; This does not work, however, if I replace ~ with the actual user name, then it works, however, I use the username of each user Can not know which will run my program. Any idea how can I get the username that started the program? ! Thanks Edit1: I have tried this, but this also includes a new line: RunCommand ('/ bin / bash', ['- - C ',' Whoami '], users); This is normal. The concept of "~" is an shell level and thus requires a separate shell elev...
Read more